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By the end of this topic, you should be able to:
A logarithm is simply another way of writing an index equation (also called an exponential equation).
The Basic Relationship:
If a^x = b, then log_a(b) = x
This means: "The power you raise a to, to get b, is x"
Example:
More Examples:
Converting Between Forms:
| Index Form | Logarithm Form |
|---|---|
| 2⁵ = 32 | log₂(32) = 5 |
| 10³ = 1000 | log₁₀(1000) = 3 |
| 4² = 16 | log₄(16) = 2 |
Just like there are laws of indices (such as a^m × a^n = a^(m+n)), there are equivalent laws for logarithms.
For any positive number a (where a > 0):
Law 1: Multiplication Rule log_a(xy) = log_a(x) + log_a(y)
This relates to the index law: a^x × a^y = a^(x+y)
Example: log₂(8 × 4) = log₂(8) + log₂(4) = 3 + 2 = 5 (Check: 8 × 4 = 32 = 2⁵, so log₂(32) = 5 ✓)
Law 2: Division Rule log_a(x/y) = log_a(x) - log_a(y)
This relates to the index law: a^x ÷ a^y = a^(x-y)
Example: log₃(27/9) = log₃(27) - log₃(9) = 3 - 2 = 1 (Check: 27/9 = 3 = 3¹, so log₃(3) = 1 ✓)
Law 3: Power Rule log_a(x^k) = k × log_a(x)
This relates to the index law: (a^x)^y = a^(xy)
Example: log₂(16) = log₂(2⁴) = 4 × log₂(2) = 4 × 1 = 4
These follow from the laws above:
log_a(a) = 1
log_a(1) = 0
log_a(a^x) = x
a^(log_a(x)) = x
log_a(1/x) = -log_a(x)
Example 1: Write 3log₂(2x+3) + log₂(5) - 2log₂(x+1) as a single logarithm
Step 1: Use the power law to move coefficients inside the logs = log₂((2x+3)³) + log₂(5) - log₂((x+1)²)
Step 2: Use the addition law = log₂(5(2x+3)³) - log₂((x+1)²)
Step 3: Use the subtraction law = log₂[5(2x+3)³/(x+1)²]
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