Logarithmic and Exponential Functions

2026 Syllabus Objectives

By the end of this topic, you should be able to:

  1. Understand the relationship between logarithms and indices, and use the laws of logarithms (excluding change of base)
  2. Understand the definition and properties of e^x and ln x, including their relationship as inverse functions and their graphs (including the graph of y = e^kx for both positive and negative values of k)
  3. Use logarithms to solve equations and inequalities in which the unknown appears in indices
  4. Use logarithms to transform a given relationship to linear form, and determine unknown constants by considering the gradient and/or intercept

1. What are Logarithms?

The Relationship Between Logarithms and Indices

A logarithm is simply another way of writing an index equation (also called an exponential equation).

The Basic Relationship:

If a^x = b, then log_a(b) = x

This means: "The power you raise a to, to get b, is x"

Example:

  • We know that 2³ = 8
  • In logarithm form, this is written as: log₂(8) = 3
  • In words: "The power you raise 2 to, to get 8, is 3"

More Examples:

  • 10² = 100, so log₁₀(100) = 2
  • 5³ = 125, so log₅(125) = 3
  • 3⁴ = 81, so log₃(81) = 4

Converting Between Forms:

Index FormLogarithm Form
2⁵ = 32log₂(32) = 5
10³ = 1000log₁₀(1000) = 3
4² = 16log₄(16) = 2

2. Laws of Logarithms

Just like there are laws of indices (such as a^m × a^n = a^(m+n)), there are equivalent laws for logarithms.

The Three Main Laws

For any positive number a (where a > 0):

Law 1: Multiplication Rule log_a(xy) = log_a(x) + log_a(y)

This relates to the index law: a^x × a^y = a^(x+y)

Example: log₂(8 × 4) = log₂(8) + log₂(4) = 3 + 2 = 5 (Check: 8 × 4 = 32 = 2⁵, so log₂(32) = 5 ✓)

Law 2: Division Rule log_a(x/y) = log_a(x) - log_a(y)

This relates to the index law: a^x ÷ a^y = a^(x-y)

Example: log₃(27/9) = log₃(27) - log₃(9) = 3 - 2 = 1 (Check: 27/9 = 3 = 3¹, so log₃(3) = 1 ✓)

Law 3: Power Rule log_a(x^k) = k × log_a(x)

This relates to the index law: (a^x)^y = a^(xy)

Example: log₂(16) = log₂(2⁴) = 4 × log₂(2) = 4 × 1 = 4

Important Special Results

These follow from the laws above:

  1. log_a(a) = 1

    • Because a¹ = a
    • "The power you raise a to, to get a, is 1"
  2. log_a(1) = 0

    • Because a⁰ = 1
    • "The power you raise a to, to get 1, is 0"
  3. log_a(a^x) = x

    • Using the power rule: log_a(a^x) = x × log_a(a) = x × 1 = x
  4. a^(log_a(x)) = x

    • This shows that raising to a power and taking a log are inverse operations
  5. log_a(1/x) = -log_a(x)

    • Because 1/x = x^(-1)
    • So log_a(x^(-1)) = -1 × log_a(x) = -log_a(x)

Using the Laws to Simplify

Example 1: Write 3log₂(2x+3) + log₂(5) - 2log₂(x+1) as a single logarithm

Step 1: Use the power law to move coefficients inside the logs = log₂((2x+3)³) + log₂(5) - log₂((x+1)²)

Step 2: Use the addition law = log₂(5(2x+3)³) - log₂((x+1)²)

Step 3: Use the subtraction law = log₂[5(2x+3)³/(x+1)²]

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