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By the end of this topic, you should be able to:
Locate approximately a root of an equation by looking at graphs and/or searching for a sign change (for example, finding two consecutive whole numbers between which a root lies)
Understand the idea of a sequence of approximations that gets closer and closer to a root, and use the correct notation for this
Understand how iterative formulas work (formulas in the form x_{n+1} = F(x_n)), how they relate to the equation being solved, and use them to find a root to a given level of accuracy. You also need to understand that iterations can sometimes fail to converge (fail to get closer to an answer)
Sometimes we need to solve equations that cannot be solved using normal algebraic methods (like factoring or using a formula). For example, equations like x³ - x² - 9 = 0 or xe^x - 2x³ - 0.5 = 0 are very difficult or impossible to solve exactly.
Numerical methods are techniques that help us find approximate solutions (close-enough answers) to these difficult equations. The two main methods you'll learn are:
A root of an equation is a value of x that makes the equation equal to zero. On a graph, roots are where the curve crosses the x-axis.
When you have a continuous function f(x) (a function with no breaks or jumps), and you find that:
Then there must be a root between a and b. This is because the function has to cross the x-axis (where f(x) = 0) to change from positive to negative.
Example: If f(2) = 5 (positive) and f(3) = -2 (negative), then there must be a root between x = 2 and x = 3.
Step 1: Choose two values of x (let's call them a and b) that you think might have a root between them.
Step 2: Calculate f(a) and f(b) by substituting these values into your function.
Step 3: Check if the signs are different:
Example: Show that f(x) = x³ - 5x + 1 has a root between x = 2 and x = 3.
Solution:
To show that a root is correct to a certain number of decimal places, you need to find its upper and lower bounds and show there's a sign change between them.
Example: Show that the root is 2.4 correct to 1 decimal place.
Solution:
This method only works when:
Always remember: You must show your working. Simply saying "there's a sign change" without calculating f(a) and f(b) will not get you marks.
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